The wavelength of the ${K_{\alpha}}$ line for an element of atomic number $43$ is $\lambda$. Then the wavelength of the ${K_{\alpha}}$ line for an element of atomic number $29$ is:

  • A
    $\frac{43}{29}\lambda$
  • B
    $\frac{42}{28}\lambda$
  • C
    $\frac{9}{4}\lambda$
  • D
    $\frac{4}{9}\lambda$

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$STATEMENT-1$: If the accelerating potential in an $X$-ray tube is increased, the wavelengths of the characteristic $X$-rays do not change. because
$STATEMENT-2$: When an electron beam strikes the target in an $X$-ray tube, part of the kinetic energy is converted into $X$-ray energy.

Frequency of the $K_{\alpha}$ $X$-ray for the element calcium $(Ca, Z = 20)$ is $8.95 \times 10^{17} \ Hz$. The frequency of the $K_{\alpha}$ $X$-ray for the element cadmium $(Cd, Z = 48)$ will be:

When an $X$-ray of wavelength $0.5 \, \mathring{A}$ passes through a metal foil of thickness $3.5 \, mm$,its intensity is reduced to one-fourth of its initial value. The absorption coefficient of the metal is ..... $mm^{-1}$.

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