The wavelength of light, while it is passing | vedclass

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(C) The frequency $f$ of light remains constant when it travels from one medium to another.Since $v = f \lambda$ and $v = \frac{c}{\mu}$, we have $\fr

Vedclass · Accepted Answer

$480$

Vedclass · Answer

(C) The frequency $f$ of light remains constant when it travels from one medium to another.Since $v = f \lambda$ and $v = \frac{c}{\mu}$, we have $\frac{c}{\mu} = f \lambda$, which implies $\mu \lambda = \frac{c}{f} = 	ext{constant}$.Therefore, $\mu_1 \lambda_1 = \mu_2 \lambda_2$.Given: $\mu_1 = \frac{4}{3}$, $\lambda_1 = 540 \ nm$, and $\mu_2 = \frac{3}{2}$.Substituting the values: $\left(\frac{4}{3}ight) 	imes 540 = \left(\frac{3}{2}ight) 	imes \lambda_2$.$\lambda_2 = 540 	imes \frac{4}{3} 	imes \frac{2}{3}$.$\lambda_2 = 540 	imes \frac{8}{9} = 60 	imes 8 = 480 \ nm$.

The wavelength of light, while it is passing through water, is $540 \ nm$. The refractive index of water is $\frac{4}{3}$. The wavelength of the same light when it is passing through a transparent medium having a refractive index of $\frac{3}{2}$ is . . . . . . $nm$.

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