The wavelengths of light absorbed by the comp | vedclass

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Question

(C) The wavelength of light absorbed by a complex is inversely proportional to the crystal field splitting energy $(\Delta_o)$,which in turn depends o

Vedclass · Accepted Answer

$\lambda_1 > \lambda_3 > \lambda_2$

Vedclass · Answer

(C) The wavelength of light absorbed by a complex is inversely proportional to the crystal field splitting energy $(\Delta_o)$,which in turn depends on the strength of the ligands.According to the spectrochemical series,the strength of the ligands is $en > H_2O$.Therefore,the crystal field splitting energy follows the order: $[Ni(en)_3]^{2+} > [Ni(H_2O)_4en]^{2+} > [Ni(H_2O)_6]^{2+}$.Since $E = \frac{hc}{\lambda}$,the energy is inversely proportional to the wavelength.Thus,the order of wavelengths absorbed is: $[Ni(H_2O)_6]^{2+} > [Ni(H_2O)_4en]^{2+} > [Ni(en)_3]^{2+}$.This corresponds to $\lambda_1 > \lambda_3 > \lambda_2$.

The wavelengths of light absorbed by the complexes $[Ni(H_2O)_6]^{2+}$,$[Ni(en)_3]^{2+}$,and $[Ni(H_2O)_4en]^{2+}$ are $\lambda_1$,$\lambda_2$,and $\lambda_3$ respectively. The correct order of wavelengths is:

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