The work functions of metals $A$ and $B$ are in the ratio $1 : 2$. If light of frequencies $f$ and $2f$ are incident on the surfaces of $A$ and $B$ respectively,the ratio of the maximum kinetic energies of photoelectrons emitted is (given that $f > f_{0A}$ and $2f > f_{0B}$).

  • A
    $1 : 1$
  • B
    $1 : 2$
  • C
    $1 : 3$
  • D
    $1 : 4$

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