The work functions of three metals A, B and C | vedclass

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(B) According to Einstein's photoelectric equation,the maximum kinetic energy $E_k$ of the emitted photoelectrons is given by:$E_k = hv - W$where $h$

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(B) According to Einstein's photoelectric equation,the maximum kinetic energy $E_k$ of the emitted photoelectrons is given by:$E_k = hv - W$where $h$ is Planck's constant,$v$ is the frequency of incident radiation,and $W$ is the work function of the metal.This equation represents a straight line $y = mx + c$ where the slope $m = h$ is constant for all metals.Therefore,the graphs for different metals must be parallel straight lines with the same slope.Given the work functions are in the order $W_A > W_B > W_C$,the threshold frequencies $v_0$ (where $E_k = 0$) follow the same order since $W = hv_0$:$(v_0)_A > (v_0)_B > (v_0)_C$This means the x-intercept for metal $A$ is the largest,followed by $B$,and then $C$.Among the given options,the graph where the lines are parallel and the x-intercepts follow the order $A > B > C$ is the correct one. Based on the provided images,the graph that shows parallel lines with the x-intercepts in the order $A > B > C$ is represented by option $B$.

The work functions of three metals $A, B$ and $C$ are $W_A, W_B$ and $W_C$ respectively. They are in decreasing order $(W_A > W_B > W_C)$. The correct graph between the maximum kinetic energy $E_k$ of the emitted electron and the frequency $v$ of the incident radiation is:

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