The yield of alkyl bromide obtained as a resu | vedclass

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Question

(A) The reaction described is the Hunsdiecker reaction,where a silver salt of a carboxylic acid reacts with bromine in $CCl_4$ to form an alkyl bromid

Vedclass · Accepted Answer

$1^o > 2^o > 3^o$ bromides

Vedclass · Answer

(A) The reaction described is the Hunsdiecker reaction,where a silver salt of a carboxylic acid reacts with bromine in $CCl_4$ to form an alkyl bromide.The mechanism involves the formation of a free radical intermediate $(R-COO^\bullet)$.The stability of free radicals follows the order: $3^o > 2^o > 1^o$.Therefore,the yield of the alkyl bromide follows the order of stability of the intermediate alkyl radical: $1^o > 2^o > 3^o$ bromides,because primary radicals are formed more easily due to less steric hindrance and the nature of the decarboxylation process in this specific reaction.

The yield of alkyl bromide obtained as a result of heating the dry silver salt of carboxylic acid with bromine in $CCl_4$ is:

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