There are 3 different rings to be worn in fou | vedclass

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(C) Wearing $3$ different rings in $4$ fingers with at most $1$ in each finger is equivalent to selecting $3$ fingers out of $4$ and arranging the $3$

Vedclass · Accepted Answer

$24$

Vedclass · Answer

(C) Wearing $3$ different rings in $4$ fingers with at most $1$ in each finger is equivalent to selecting $3$ fingers out of $4$ and arranging the $3$ different rings in those selected fingers.Since the rings are different,the order of placement matters.This is equivalent to finding the number of permutations of $4$ items taken $3$ at a time,which is given by $P(4, 3)$.$P(4, 3) = \frac{4!}{(4-3)!} = \frac{4 	imes 3 	imes 2 	imes 1}{1} = 24$ ways.Therefore,the total number of ways is $24$.

There are $3$ different rings to be worn in four fingers with at most $1$ in each finger. In how many ways can this be done?

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