There are $x^{2}-2$ students in the class. $x^{3}-3x^{2}+5x-3$ chocolates are distributed between them. Each student should get the maximum possible number of chocolates. Find the number of chocolates received by each student and the number of chocolates left undistributed $(x \in N)$.

(N/A) To find the number of chocolates received by each student and the remainder,we perform polynomial division of $(x^{3}-3x^{2}+5x-3)$ by $(x^{2}-2)$.
Step $1$: Divide $x^{3}$ by $x^{2}$ to get $x$.
Step $2$: Multiply $x$ by $(x^{2}-2)$ to get $x^{3}-2x$.
Step $3$: Subtract $(x^{3}-2x)$ from $(x^{3}-3x^{2}+5x-3)$ to get $-3x^{2}+7x-3$.
Step $4$: Divide $-3x^{2}$ by $x^{2}$ to get $-3$.
Step $5$: Multiply $-3$ by $(x^{2}-2)$ to get $-3x^{2}+6$.
Step $6$: Subtract $(-3x^{2}+6)$ from $(-3x^{2}+7x-3)$ to get $7x-9$.
Thus,each student receives $x-3$ chocolates,and the number of chocolates left undistributed is $7x-9$.