There are ldots ldots ldots ldots terms in th | vedclass

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(B) The given arithmetic progression $(A.P.)$ is $5, 10, 15, \ldots, 200$.Here,the first term $a = 5$.The common difference $d = 10 - 5 = 5$.The last

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$40$

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(B) The given arithmetic progression $(A.P.)$ is $5, 10, 15, \ldots, 200$.Here,the first term $a = 5$.The common difference $d = 10 - 5 = 5$.The last term $a_n = 200$.The formula for the $n^{th}$ term of an $A.P.$ is $a_n = a + (n - 1)d$.Substituting the values: $200 = 5 + (n - 1)5$.$200 - 5 = (n - 1)5$.$195 = (n - 1)5$.$n - 1 = 195 / 5$.$n - 1 = 39$.$n = 39 + 1 = 40$.Therefore,there are $40$ terms in the given $A.P.$

There are $\ldots \ldots \ldots \ldots$ terms in the finite $A.P.$ $5, 10, 15, \ldots, 200$.

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