There are $n$ white and $n$ black balls marked $1, 2, 3, \ldots, n$. The number of ways in which we can arrange these balls in a row so that neighbouring balls are of different colours is

  • A
    $(n!)^2$
  • B
    $(2n)!$
  • C
    $2(n!)^2$
  • D
    $\frac{(2n)!}{(n!)^2}$

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