There are four convex lenses L_{1}, L_{2}, L_ | vedclass

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(C) For a telescope,the length $L$ is given by $L = f_{o} + f_{e} = 10 \ cm$.The magnifying power $M$ is given by $M = \frac{f_{o}}{f_{e}} = 4$.From t

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$L_{4}, L_{1}$

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(C) For a telescope,the length $L$ is given by $L = f_{o} + f_{e} = 10 \ cm$.The magnifying power $M$ is given by $M = \frac{f_{o}}{f_{e}} = 4$.From the second equation,$f_{o} = 4f_{e}$.Substituting this into the first equation: $4f_{e} + f_{e} = 10 \ cm$,which gives $5f_{e} = 10 \ cm$,so $f_{e} = 2 \ cm$.Then,$f_{o} = 4 	imes 2 \ cm = 8 \ cm$.Thus,the objective lens has a focal length of $8 \ cm$ $(L_{4})$ and the eye lens has a focal length of $2 \ cm$ $(L_{1})$.Therefore,the objective and eye lenses are $L_{4}$ and $L_{1}$ respectively.

There are four convex lenses $L_{1}, L_{2}, L_{3}$ and $L_{4}$ with focal lengths $2 \ cm, 4 \ cm, 6 \ cm$ and $8 \ cm$ respectively. Two of these lenses form a telescope of length $10 \ cm$ and magnifying power $4$. The objective and eye lenses are respectively:

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