When a telescope is adjusted for parallel lig | vedclass

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(C) When a telescope is adjusted for parallel light (normal adjustment),the length of the telescope tube is $L = f_o + f_e = 80 \,cm$. The magnifying

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$76 \,cm, 4 \,cm$

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(C) When a telescope is adjusted for parallel light (normal adjustment),the length of the telescope tube is $L = f_o + f_e = 80 \,cm$. The magnifying power $M$ of the telescope is given by $M = \frac{f_o}{f_e} = 19$. From the second equation,$f_o = 19 f_e$. Substituting this into the first equation: $19 f_e + f_e = 80 \,cm$. $20 f_e = 80 \,cm$,which gives $f_e = 4 \,cm$. Then,$f_o = 19 	imes 4 \,cm = 76 \,cm$. Thus,the focal lengths are $76 \,cm$ and $4 \,cm$.

When a telescope is adjusted for parallel light,the distance of the objective from the eyepiece is found to be $80 \,cm$. The magnifying power of the telescope is $19$. The focal lengths of the lenses are

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