(C) The elongation due to a tensile force is given by the formula: $\frac{\Delta l}{l} = \frac{F}{A \cdot Y}$.Given: $F = 33000 \,N$, $A = 10^{-3} \,m

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(C) The elongation due to a tensile force is given by the formula: $\frac{\Delta l}{l} = \frac{F}{A \cdot Y}$.Given: $F = 33000 \,N$, $A = 10^{-3} \,m^2$, $Y = 3 \times 10^{11} \,N/m^2$.Substituting the values: $\frac{\Delta l}{l} = \frac{33000}{10^{-3} \times 3 \times 10^{11}} = \frac{33000}{3 \times 10^8} = 11 \times 10^{-5}$.The elongation due to thermal expansion is given by: $\frac{\Delta l}{l} = \alpha \Delta T$.Given: $\alpha = 1.1 \times 10^{-5} /{ }^{\circ}C$.Equating the two elongations: $11 \times 10^{-5} = 1.1 \times 10^{-5} \times \Delta T$.Solving for $\Delta T$: $\Delta T = \frac{11 \times 10^{-5}}{1.1 \times 10^{-5}} = 10^{\circ}C$.

Class 11 Physics Mechanical Properties of Solids Young’s Modulus

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There is some change in length when a $33000 \,N$ tensile force is applied on a steel rod of area of cross-section $10^{-3} \,m^2$. The change of temperature required to produce the same elongation, if the steel rod is heated, is (The modulus of elasticity is $3 \times 10^{11} \,N/m^2$ and the coefficient of linear expansion of steel is $1.1 \times 10^{-5} /{ }^{\circ}C$). (in $^{\circ}C$)

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Two exactly similar wires of steel and copper are stretched by equal forces. If the total elongation is $2 \,cm$,then how much is the elongation in steel and copper wire respectively? Given,$Y_{\text{steel}} = 20 \times 10^{11} \,dyne/cm^2$,$Y_{\text{copper}} = 12 \times 10^{11} \,dyne/cm^2$.

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Two wires $A$ and $B$ are made of the same material. Their diameters are in the ratio of $1: 2$ and their lengths are in the ratio of $1: 3$. If they are stretched by the same force,then the increase in their lengths will be in the ratio of:

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$A$ meter scale of mass $m$,Young's modulus $Y$,and cross-sectional area $A$ is hung vertically from the ceiling at the zero mark. The separation between the $30\ cm$ and $70\ cm$ marks will be: (Assume $\frac{mg}{AY}$ is dimensionless)

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$A$ force $F$ is applied to a wire of length $L$ and radius $r$,resulting in an extension $l$. What will be the extension in a wire of length $2L$ and radius $2r$ when a force $2F$ is applied?

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$A$ steel rail of length $5\,m$ and area of cross-section $40\,cm^2$ is prevented from expanding along its length while the temperature rises by $10\,^{\circ}C$. If the coefficient of linear expansion and Young's modulus of steel are $1.2\times10^{-5}\,K^{-1}$ and $2\times10^{11}\,N/m^2$ respectively,the force developed in the rail is approximately:

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Two exactly similar wires of steel and copper are stretched by equal forces. If the total elongation is $2 \,cm$,then how much is the elongation in steel and copper wire respectively? Given,$Y_{\text{steel}} = 20 \times 10^{11} \,dyne/cm^2$,$Y_{\text{copper}} = 12 \times 10^{11} \,dyne/cm^2$.

Two wires $A$ and $B$ are made of the same material. Their diameters are in the ratio of $1: 2$ and their lengths are in the ratio of $1: 3$. If they are stretched by the same force,then the increase in their lengths will be in the ratio of:

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$A$ force $F$ is applied to a wire of length $L$ and radius $r$,resulting in an extension $l$. What will be the extension in a wire of length $2L$ and radius $2r$ when a force $2F$ is applied?

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