Though the electron drift velocity is small and electron charge is very small, a conductor can carry an appreciably large current because

  • A
    electron number density depends on temperature
  • B
    electron number density is very large
  • C
    relaxation time is small
  • D
    drift velocity of electron is very large

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$A$ current of $2 \,A$ is passing through a metal wire of cross-sectional area $2 \times 10^{-6} \,m^{2}$. If the number density of free electrons in the wire is $5 \times 10^{26} \,m^{-3}$, the drift speed of electrons is (Given, $e = 1.6 \times 10^{-19} \,C$)

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There are $0.8 \times 10^{23}$ free electrons $/ cm^3$ in copper. If a $0.2 \, A$ current is flowing in a copper wire, then the drift velocity of electrons will be, given the cross-sectional area of the wire is $0.01 \, cm^2$.

Which particles are responsible for the conductivity of metals?

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