Three amplifiers,each having a voltage gain of $10$,are connected in series. The resultant gain would be

In an $N-P-N$ transistor circuit,the common emitter configuration is used. $A$ load resistor $R_L$ is connected to the collector and a base resistor $R_B$ is connected to the base. Given $V_{CC} = 8V$,$V_{CE} = 4V$,$V_{BE} = 0.6V$,collector current $I_C = 4mA$,and current gain $\beta = 100$,find the values of $R_L$ and $R_B$ respectively.

For a transistor amplifier,the voltage gain:

In the circuit shown in the figure,when the input voltage $V_i$ is $10\, V$,$V_{BE}$ is zero and $V_{CE}$ is also zero. Find the values of $I_B$,$I_C$,and $\beta$.

In a common emitter transistor amplifier,the audio signal voltage across the collector is $3\,V$. The resistance of the collector is $3\,k\Omega$. If the current gain is $100$ and the base resistance is $2\,k\Omega$,what are the voltage and power gain of the amplifier?

In common emitter mode of a transistor, the d.c. current gain is $20$, and the emitter current is $7 \,mA$. The collector current is (in $/ 3 \,mA$)