In common emitter mode of a transistor, the d.c. current gain is $20$, and the emitter current is $7 \,mA$. The collector current is (in $/ 3 \,mA$)

$A$ transistor has a voltage gain '$A$'. If a fraction '$\beta$' of its output is fed back to the input of the transistor,then the transistor becomes an oscillator when:

The correct relation between $\alpha$ (ratio of collector current to emitter current) and $\beta$ (ratio of collector current to base current) of a transistor is :

The input voltage applied to a $CE$ amplifier is $v_i = 0.2 \sin(1000t) \text{ V}$. If the voltage gain of the amplifier is $10$,the equation for the output voltage is ....... $\text{V}$.

In a transistor,the forward bias is always kept smaller than the reverse bias. The correct reason is:

For $I_b = 20 \ \mu A$ and $\beta = 100$,the value of the emitter current is ........ $mA$.