Three circuit connections of a $PNP$ transistor are given below. Which of the following represents the Common-Emitter configuration?

The current amplification factor of a transistor is $50$. The input resistance when used in common emitter mode is $1 \text{ k}\Omega$. The peak value of the collector current for an a.c. input voltage of $0.01 \text{ V}$ peak is:

In a common emitter transistor amplifier circuit,the input resistance is $1.8 \text{ k}\Omega$ and the output is obtained across a load resistance of $9 \text{ k}\Omega$. The alternating current gain is $70$. Corresponding to an a.c. input voltage of $6 \text{ mV}$,the output voltage will be: (in $\text{ V}$)

For a common emitter configuration,if $\alpha$ and $\beta$ have their usual meanings,the incorrect relation between $\alpha$ and $\beta$ is

$A$ $CE$ amplifier has a voltage gain of $G$. The transistor used has a transconductance of $0.03 \ mho$ and a current gain of $25$. If this transistor is replaced by another transistor with a transconductance of $0.02 \ mho$ and a current gain of $20$,the new voltage gain will be ........

In the transistor circuit shown,the base current is $35 \mu A$. The value of the resistor $R_b$ is......$ k \Omega$.