Three plates of common surface area A are con | vedclass

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Question

(D) The given circuit consists of three plates. Let the middle plate be connected to terminal $A$ and the top and bottom plates be connected together

Vedclass · Accepted Answer

$\frac{2\varepsilon_0 A}{d}$

Vedclass · Answer

(D) The given circuit consists of three plates. Let the middle plate be connected to terminal $A$ and the top and bottom plates be connected together to terminal $B$.This arrangement forms two capacitors in parallel,each formed by the middle plate and one of the outer plates.The capacitance of each capacitor is $C = \frac{\varepsilon_0 A}{d}$.Since the two capacitors are in parallel,the effective capacitance is $C_{eq} = C + C = 2C$.Substituting the value of $C$,we get $C_{eq} = \frac{2\varepsilon_0 A}{d}$.

Three plates of common surface area $A$ are connected as shown. The effective capacitance will be

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