To establish an instantaneous current of 2,A | vedclass

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(C) The current $I$ flowing through a capacitor is given by the relation $I = C \frac{dV}{dt}$,where $C$ is the capacitance and $\frac{dV}{dt}$ is the

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$2 	imes 10^6\,V/s$

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(C) The current $I$ flowing through a capacitor is given by the relation $I = C \frac{dV}{dt}$,where $C$ is the capacitance and $\frac{dV}{dt}$ is the rate of change of potential difference across the plates.Given: $I = 2\,A$ and $C = 1\,\mu F = 1 	imes 10^{-6}\,F$.Rearranging the formula to find the rate of change of potential difference:$\frac{dV}{dt} = \frac{I}{C}$Substituting the given values:$\frac{dV}{dt} = \frac{2}{1 	imes 10^{-6}}\,V/s$$\frac{dV}{dt} = 2 	imes 10^6\,V/s$.

To establish an instantaneous current of $2\,A$ through a $1\,\mu F$ capacitor,the potential difference across the capacitor plates should be changed at the rate of:

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