To gain $1 \ mole$ $Mg$ from $Mg^{2+}$ and $1 \ mole$ $Al$ from $Al^{3+}$,how many Coulombs of electricity are required respectively?

  • A
    $193000 \ C$ and $289500 \ C$
  • B
    $96500 \ C$ and $193000 \ C$
  • C
    $289500 \ C$ and $193000 \ C$
  • D
    $193000 \ C$ and $96500 \ C$

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Similar Questions

Match the following and select the correct option for the quantity of electricity,in $C \ mol^{-1}$,required to deposit various metals at the cathode:
List-$I$ List-$II$
$a. \ Ag^{+}$ $i. \ 386000 \ C \ mol^{-1}$
$b. \ Mg^{2+}$ $ii. \ 289500 \ C \ mol^{-1}$
$c. \ Al^{3+}$ $iii. \ 96500 \ C \ mol^{-1}$
$d. \ Ti^{4+}$ $iv. \ 193000 \ C \ mol^{-1}$

Total charge on $1 \, \text{mole}$ of a monovalent metal ion is equal to

If $96500 \ C$ of electricity liberates one gram equivalent of any substance,the time taken for a current of $0.15 \ A$ to deposit $20 \ mg$ of copper from a solution of copper sulphate is (Chemical equivalent of copper = $32$).

The relation between Faraday constant $(F)$,chemical equivalent $(E)$,and electrochemical equivalent $(Z)$ is

$96.5$ amperes current is passed through the molten $AlCl_3$ for $100$ seconds. The mass of aluminium deposited at the cathode is (atomic weight of $Al = 27$ $u$). (in $g$)

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