To get three images of a single object, the angle between the two plane mirrors should be (in $^{\circ}$)

Light rays fall on a plane mirror and form a real image. Therefore,the incident rays are:

$A$ ray of light travelling in the direction $\frac{1}{2}(\hat{i}+\sqrt{3} \hat{j})$ is incident on a plane mirror. After reflection,it travels along the direction $\frac{1}{2}(\hat{i}-\sqrt{3} \hat{j})$. The angle of incidence is: (in $^{\circ}$)

Two mirrors,labeled $LM$ for left mirror and $RM$ for right mirror in the adjacent figure,are parallel to each other and $3.0 \, m$ apart. $A$ person standing $1.0 \, m$ from the right mirror $(RM)$ looks into this mirror and sees a series of images. How far from the person is the second closest image seen in the right mirror $(RM)$ (in $, m$)?

$A$ light bulb is placed between two plane mirrors inclined at an angle of $60^{\circ}$. The number of images formed is:

$A$ person is in a room whose ceiling and two adjacent walls are mirrors. How many images are formed?