Torques tau_1 and tau_2 are required for a ma | vedclass

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(B) The torque $	au$ acting on a magnetic needle of magnetic moment $M$ in a uniform magnetic field $B$ is given by the formula: $	au = M B \sin 	h

Vedclass · Accepted Answer

$	au_1: 	au_2$

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(B) The torque $	au$ acting on a magnetic needle of magnetic moment $M$ in a uniform magnetic field $B$ is given by the formula: $	au = M B \sin 	heta$.Here,$	heta$ is the angle between the magnetic moment and the magnetic field.It is given that the needle remains perpendicular to the magnetic field,so $	heta = 90^{\circ}$.Since $\sin 90^{\circ} = 1$,the torque becomes $	au = M B$.For the two different places with magnetic fields $B_1$ and $B_2$,the torques are $	au_1 = M B_1$ and $	au_2 = M B_2$.Taking the ratio of the two torques: $\frac{	au_1}{	au_2} = \frac{M B_1}{M B_2} = \frac{B_1}{B_2}$.Therefore,the ratio $B_1 : B_2$ is equal to $	au_1 : 	au_2$.

Torques $\tau_1$ and $\tau_2$ are required for a magnetic needle to remain perpendicular to the magnetic fields of $B_1$ and $B_2$ at two different places. The ratio of $B_1: B_2$ is equal to

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