Total number of geometrical isomers possible | vedclass

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(C) $1$. $[NiCl_4]^{2-}$: This is a tetrahedral complex ($sp^3$ hybridization). Tetrahedral complexes do not exhibit geometrical isomerism. Number of

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$4$

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(C) $1$. $[NiCl_4]^{2-}$: This is a tetrahedral complex ($sp^3$ hybridization). Tetrahedral complexes do not exhibit geometrical isomerism. Number of isomers = $0$.$2$. $[CoCl_2(NH_3)_4]^{+}$: This is an octahedral complex of the type $[MA_4B_2]$. It shows $2$ geometrical isomers ($cis$ and $trans$).$3$. $[Co(NH_3)_3(NO_2)_3]$: This is an octahedral complex of the type $[MA_3B_3]$. It shows $2$ geometrical isomers ($fac$ and $mer$).$4$. $[Co(NH_3)_5Cl]^{2+}$: This is an octahedral complex of the type $[MA_5B]$. It does not show geometrical isomerism. Number of isomers = $0$.Total number of geometrical isomers = $0 + 2 + 2 + 0 = 4$.

Total number of geometrical isomers possible for the complexes $[NiCl_4]^{2-}$,$[CoCl_2(NH_3)_4]^{+}$,$[Co(NH_3)_3(NO_2)_3]$ and $[Co(NH_3)_5Cl]^{2+}$ is

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