Translate the following statement into a chemical equation and balance it:
$(a)$ Aluminium chloride reacts with ammonium hydroxide to form a gelatinous white precipitate of aluminium hydroxide and a salt of ammonium chloride.
$(a)$ Aluminium chloride reacts with ammonium hydroxide to form a gelatinous white precipitate of aluminium hydroxide and a salt of ammonium chloride.
(A) The chemical equation for the reaction is:
$AlCl_{3}(aq) + 3NH_{4}OH(aq) \longrightarrow Al(OH)_{3}(s) \downarrow + 3NH_{4}Cl(aq)$
Explanation:
$1$. Aluminium chloride $(AlCl_{3})$ reacts with ammonium hydroxide $(NH_{4}OH)$.
$2$. This is a double displacement reaction where aluminium hydroxide $(Al(OH)_{3})$ is formed as a gelatinous white precipitate,and ammonium chloride $(NH_{4}Cl)$ remains in the solution.
$3$. To balance the equation,we ensure the number of atoms of each element is equal on both sides: there is $1$ $Al$ atom,$3$ $Cl$ atoms,$3$ $N$ atoms,$15$ $H$ atoms,and $3$ $O$ atoms on both sides.
$AlCl_{3}(aq) + 3NH_{4}OH(aq) \longrightarrow Al(OH)_{3}(s) \downarrow + 3NH_{4}Cl(aq)$
Explanation:
$1$. Aluminium chloride $(AlCl_{3})$ reacts with ammonium hydroxide $(NH_{4}OH)$.
$2$. This is a double displacement reaction where aluminium hydroxide $(Al(OH)_{3})$ is formed as a gelatinous white precipitate,and ammonium chloride $(NH_{4}Cl)$ remains in the solution.
$3$. To balance the equation,we ensure the number of atoms of each element is equal on both sides: there is $1$ $Al$ atom,$3$ $Cl$ atoms,$3$ $N$ atoms,$15$ $H$ atoms,and $3$ $O$ atoms on both sides.
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