The correct order of bond angle is:

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Question

(A) The bond angle depends on the electronegativity of the central atom and the size of the surrounding atoms. As we move down the group $16$ from $O$

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$H_2O > H_2S > H_2Se > H_2Te$

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(A) The bond angle depends on the electronegativity of the central atom and the size of the surrounding atoms. As we move down the group $16$ from $O$ to $Te$,the electronegativity of the central atom decreases. Consequently,the bond pairs move further away from the central atom,and the bond angle decreases. Thus,the correct order is $H_2O (104.5^{\circ}) > H_2S (92.1^{\circ}) > H_2Se (91^{\circ}) > H_2Te (90^{\circ})$.

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