Twenty-four men can complete a work in sixtee | vedclass

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(B) $1$ man's $1$ day's work $= \frac{1}{24 	imes 16} = \frac{1}{384}$ units.$1$ woman's $1$ day's work $= \frac{1}{32 	imes 24} = \frac{1}{768}$ un

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$24$

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(B) $1$ man's $1$ day's work $= \frac{1}{24 	imes 16} = \frac{1}{384}$ units.$1$ woman's $1$ day's work $= \frac{1}{32 	imes 24} = \frac{1}{768}$ units.$16$ men and $16$ women's $1$ day's work $= 16 	imes \frac{1}{384} + 16 	imes \frac{1}{768} = \frac{1}{24} + \frac{1}{48} = \frac{2+1}{48} = \frac{3}{48} = \frac{1}{16}$ units.Work done in $12$ days $= 12 	imes \frac{1}{16} = \frac{3}{4}$ units.Remaining work $= 1 - \frac{3}{4} = \frac{1}{4}$ units.Let $x$ be the number of additional men required. Total men $= 16 + x$.Work done by $(16+x)$ men and $16$ women in $2$ days $= (16+x) 	imes 2 	imes \frac{1}{384} + 16 	imes 2 	imes \frac{1}{768} = \frac{1}{4}$.$\frac{16+x}{192} + \frac{32}{768} = \frac{1}{4}$.$\frac{16+x}{192} + \frac{1}{24} = \frac{1}{4}$.$\frac{16+x}{192} = \frac{1}{4} - \frac{1}{24} = \frac{6-1}{24} = \frac{5}{24}$.$16+x = \frac{5}{24} 	imes 192 = 5 	imes 8 = 40$.$x = 40 - 16 = 24$.

Twenty-four men can complete a work in sixteen $days$. Thirty-two women can complete the same work in twenty-four $days$. Sixteen men and sixteen women started working and worked for twelve $days$. How many more men are to be added to complete the remaining work in $2$ $days$?

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