Two balanced dice are rolled simultaneously. Then,the probability that the numbers on both the dice are prime is ...........

  • A
    $\frac{2}{9}$
  • B
    $\frac{1}{4}$
  • C
    $\frac{1}{3}$
  • D
    $\frac{1}{6}$

Explore More

Similar Questions

The probability that a non-leap year selected at random will contain $53$ Sundays is

$A$ balanced die is thrown once. Find the probability of getting a prime number.

At a fete, cards bearing numbers $1$ to $1000$, one number on one card, are put in a box. Each player selects one card at random and that card is not replaced. If the selected card has a perfect square greater than $500$, the player wins a prize. What is the probability that:
$(i)$ the first player wins a prize?
$(ii)$ the second player wins a prize, if the first has won?

If $P(A)$ denotes the probability of an event $A$,then

$A$ student says that if you throw a die,it will show up $1$ or not $1$. Therefore,the probability of getting $1$ and the probability of getting 'not $1$' each is equal to $\frac{1}{2}$. Is this correct? Give reasons.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo