Two bulbs are connected in parallel. Bulb A i | vedclass

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(B) When bulbs are connected in parallel,the potential difference $V$ across each bulb is the same.The power consumed by a bulb is given by the formul

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$R_A < R_B$

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(B) When bulbs are connected in parallel,the potential difference $V$ across each bulb is the same.The power consumed by a bulb is given by the formula $P = \frac{V^2}{R}$.Since the brightness of a bulb is directly proportional to the power consumed $(P \propto 	ext{Brightness})$,and $P \propto \frac{1}{R}$ for a constant voltage $V$,it follows that the bulb with lower resistance consumes more power and is therefore brighter.Given that bulb $A$ is brighter than bulb $B$,it implies $P_A > P_B$.Therefore,$R_A < R_B$.

Two bulbs are connected in parallel. Bulb $A$ is brighter than bulb $B$. If $R_A$ and $R_B$ are their resistances respectively,then:

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