Two capacitors $C_1$ and $C_2 = 2C_1$ are connected in a circuit with a switch between them as shown in the figure. Initially,the switch is open and $C_1$ holds charge $Q$. The switch is closed. At steady state,the charge on the capacitors will be:

  • A
    $Q, 2Q$
  • B
    $\frac{Q}{2}, \frac{2Q}{3}$
  • C
    $\frac{3Q}{2}, 3Q$
  • D
    $\frac{Q}{3}, \frac{2Q}{3}$

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