Class 12PhysicsElectric Potential and CapacitanceEquivalent Capacitance of Capacitor connected in Series and Parallel
EasyTwo capacitors each having a capacitance $2 \times 10^{-6} \ F$ and a breakdown voltage $5000 \ V$,are joined in series. What will be the resultant capacitance and the breakdown voltage of the combination?
- A$4 \times 10^{-6} \ F$ and $1000 \ V$
- B$10^{-6} \ F$ and $10000 \ V$
- C$2 \times 10^{-6} \ F$ and $5000 \ V$
- D$10^{-6} \ F$ and $2500 \ V$
Explore More
Similar Questions
The effective capacitance between points $X$ and $Y$ is ....... $\mu F$.
Difficult
View SolutionThe minimum value of effective capacitance that can be obtained by combining $3$ capacitors of capacitances $1 \ pF, 2 \ pF$ and $4 \ pF$ is
DifficultKCET 2017
View SolutionThe equivalent capacitance in the circuit between $A$ and $B$ will be.....$\mu F$.
Easy
View SolutionWhen three capacitors of equal capacities are connected in parallel and one of the same capacity is connected in series with the combination,the resultant capacity is $4.5 \mu F$. The capacity of each capacitor is: (in $\mu F$)
Three parallel plate air capacitors are connected in parallel. Each capacitor has plate area $\frac{A}{3}$ and the separation between the plates is $d, 2d$ and $3d$ respectively. The equivalent capacity of the combination is ($\varepsilon_0 =$ absolute permittivity of free space).
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo