Two capacitors of same capacity are first joined in series and then in parallel. The ratio of resultant capacity in series to that in parallel combination will be

Three equal capacitors,each with capacitance $C$,are connected as shown in the figure. The equivalent capacitance between $A$ and $B$ is:

An infinite number of capacitors with capacitances $C, 4C, 16C, ... \infty$ are connected in series. What is the equivalent capacitance of the combination in terms of $C$?

Three capacitors,each of value $1 \ \mu\text{F}$,are connected in such a way that the resultant capacitance is $1.5 \ \mu\text{F}$. Then:

Four capacitors of equal capacity have an equivalent capacitance $C_{1}$ when connected in series and an equivalent capacitance $C_{2}$ when connected in parallel. The ratio $\frac{C_{2}}{C_{1}}$ is:

In the circuit diagram shown in the adjoining figure,the resultant capacitance between $P$ and $Q$ is ........ $\mu F$.