Two capacitors,one of capacity $\frac{C}{2}$ and the other of capacity $C$,are connected to a battery of voltage $V$ as shown. The work done in charging both the capacitors fully is
- A$\frac{1}{2} CV^2$
- B$\frac{3}{4} CV^2$
- C$\frac{3}{2} CV^2$
- D$2 CV^2$
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