Two coils have a mutual inductance 0.005 , H. | vedclass

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(B) The induced $e.m.f.$ in the second coil is given by $e = M \frac{di}{dt}$.Given $M = 0.005 \, H$,$I = I_0 \sin(\omega t)$,$I_0 = 10 \, A$,and $\om

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$5\pi \, V$

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(B) The induced $e.m.f.$ in the second coil is given by $e = M \frac{di}{dt}$.Given $M = 0.005 \, H$,$I = I_0 \sin(\omega t)$,$I_0 = 10 \, A$,and $\omega = 100\pi \, rad/s$.Substituting the expression for $I$:$e = M \frac{d}{dt} (I_0 \sin(\omega t)) = M I_0 \omega \cos(\omega t)$.The maximum value of $e.m.f.$ $(e_{\max})$ occurs when $\cos(\omega t) = 1$.$e_{\max} = M I_0 \omega$.Substituting the values:$e_{\max} = 0.005 	imes 10 	imes 100\pi = 5\pi \, V$.

Two coils have a mutual inductance $0.005 \, H$. The current changes in the first coil according to the equation $I = I_0 \sin(\omega t)$,where $I_0 = 10 \, A$ and $\omega = 100\pi \, rad/s$. The maximum value of the $e.m.f.$ in the second coil is:

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