Two coins are tossed simultaneously $400$ times with the following frequencies of different outcomes:
Two heads: $100$ times
One head: $220$ times
No head: $80$ times
Find the probability of occurrence of each of these events.
Two heads: $100$ times
One head: $220$ times
No head: $80$ times
Find the probability of occurrence of each of these events.
(N/A) The total number of trials is $400$.
$1$. Probability of getting two heads = (Number of times two heads occurred) / (Total number of trials) = $100 / 400 = 0.25$.
$2$. Probability of getting one head = (Number of times one head occurred) / (Total number of trials) = $220 / 400 = 0.55$.
$3$. Probability of getting no head = (Number of times no head occurred) / (Total number of trials) = $80 / 400 = 0.20$.
$1$. Probability of getting two heads = (Number of times two heads occurred) / (Total number of trials) = $100 / 400 = 0.25$.
$2$. Probability of getting one head = (Number of times one head occurred) / (Total number of trials) = $220 / 400 = 0.55$.
$3$. Probability of getting no head = (Number of times no head occurred) / (Total number of trials) = $80 / 400 = 0.20$.
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