Two concentric coils each of radius equal to | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The magnetic field at the center of a circular coil of radius $r$ carrying current $i$ is given by $B = \frac{\mu_0 i}{2r}$.Given $r = 4 \pi 	ext

Vedclass · Accepted Answer

$13 	imes 10^{-5} 	ext{ Wb m}^{-2}$

Vedclass · Answer

(A) The magnetic field at the center of a circular coil of radius $r$ carrying current $i$ is given by $B = \frac{\mu_0 i}{2r}$.Given $r = 4 \pi 	ext{ cm} = 4 \pi 	imes 10^{-2} 	ext{ m}$.For the first coil with current $i_1 = 10 	ext{ A}$:$B_1 = \frac{\mu_0 	imes 10}{2 	imes 4 \pi 	imes 10^{-2}} = \frac{4 \pi 	imes 10^{-7} 	imes 10}{8 \pi 	imes 10^{-2}} = 0.5 	imes 10^{-4} 	ext{ T} = 5 	imes 10^{-5} 	ext{ T}$.For the second coil with current $i_2 = 24 	ext{ A}$:$B_2 = \frac{\mu_0 	imes 24}{2 	imes 4 \pi 	imes 10^{-2}} = \frac{4 \pi 	imes 10^{-7} 	imes 24}{8 \pi 	imes 10^{-2}} = 1.2 	imes 10^{-4} 	ext{ T} = 12 	imes 10^{-5} 	ext{ T}$.Since the coils are at right angles,the resultant magnetic field $B$ is given by $B = \sqrt{B_1^2 + B_2^2}$.$B = \sqrt{(5 	imes 10^{-5})^2 + (12 	imes 10^{-5})^2} = \sqrt{25 + 144} 	imes 10^{-5} 	ext{ T} = \sqrt{169} 	imes 10^{-5} 	ext{ T} = 13 	imes 10^{-5} 	ext{ Wb m}^{-2}$.

Two concentric coils each of radius equal to $4 \pi \text{ cm}$ are placed at right angles to each other. If $10 \text{ A}$ and $24 \text{ A}$ are the currents flowing through the coils,respectively,the magnetic induction at the center of the coils will be

Similar Questions

Which scientist established that electricity and magnetism are interrelated?

$A$ horizontal overhead power line carries a current of $90 \;A$ in east to west direction. What is the magnitude and direction of the magnetic field due to the current $1.5 \;m$ below the line?

$A$ long current-carrying wire produces a magnetic field of $1 \ T$ at a distance of $r$. What will be the magnetic field at distances of $(a)$ $\frac{r}{2}$,$(b)$ $2r$,and $(c)$ $3r$?

$A$ wire carrying current $i$ is shaped as shown. Section $AB$ is a quarter circle of radius $r$. The magnetic field at the center $C$ is directed:

$A$ circular loop of a wire and a long straight wire carry currents $I_c$ and $I_e$,respectively,as shown in the figure. Assuming that these are placed in the same plane,the magnetic field will be zero at the centre of the loop when the separation $H$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module