Two dice are thrown. If the first die shows 5 | vedclass

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(D) When two dice are thrown,the total number of outcomes is $36$. Given that the first die shows $5$,the possible outcomes are $(5, 1), (5, 2), (5, 3

Vedclass · Accepted Answer

$\frac{2}{3}$

Vedclass · Answer

(D) When two dice are thrown,the total number of outcomes is $36$. Given that the first die shows $5$,the possible outcomes are $(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)$. There are $6$ such outcomes. We need the sum of the numbers to be $8$ or more than $8$. The outcomes satisfying this condition are $(5, 3), (5, 4), (5, 5), (5, 6)$. There are $4$ such outcomes. Therefore,the required probability is $\frac{4}{6} = \frac{2}{3}$.

Two dice are thrown. If the first die shows $5$,then the probability that the sum of the numbers on both dice is $8$ or more than $8$ is:

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