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(D) The resistance $R$ of each resistor is calculated using the formula $P = \frac{V^2}{R}$,which gives $R = \frac{V^2}{P}$.Given $P = 320 \ W$ and $V

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$20$

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(D) The resistance $R$ of each resistor is calculated using the formula $P = \frac{V^2}{R}$,which gives $R = \frac{V^2}{P}$.Given $P = 320 \ W$ and $V = 220 \ V$,we have $R = \frac{220^2}{320} \ \Omega$.When two identical resistors are connected in series to a supply voltage $V_{total} = 110 \ V$,the voltage across each resistor is $V' = \frac{V_{total}}{2} = \frac{110}{2} = 55 \ V$.The power generated in each resistor is $P' = \frac{(V')^2}{R}$.Substituting the values: $P' = \frac{55^2}{R} = \frac{55^2}{220^2 / 320} = \frac{55^2 	imes 320}{220^2}$.Since $\frac{55}{220} = \frac{1}{4}$,we get $P' = (\frac{1}{4})^2 	imes 320 = \frac{1}{16} 	imes 320 = 20 \ W$.

Two electric resistors have equal values of resistance $R$. Each can be operated with a power of $320 \ W$ at $220 \ V$. If the two resistors are connected in series to a $110 \ V$ electric supply,then the power generated in each resistor is (in $W$)

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