Two equal resistances when connected in serie | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let the value of each resistance be $R$ and the voltage of the battery be $V$.When connected in series,the equivalent resistance is $R_s = R + R =

Vedclass · Accepted Answer

$240$

Vedclass · Answer

(B) Let the value of each resistance be $R$ and the voltage of the battery be $V$.When connected in series,the equivalent resistance is $R_s = R + R = 2R$.The power consumed in series is $P_s = \frac{V^2}{R_s} = \frac{V^2}{2R} = 60 \, W$.From this,we get $\frac{V^2}{R} = 120 \, W$.When connected in parallel,the equivalent resistance is $R_p = \frac{R 	imes R}{R + R} = \frac{R}{2}$.The power consumed in parallel is $P_p = \frac{V^2}{R_p} = \frac{V^2}{R/2} = 2 \left( \frac{V^2}{R} ight)$.Substituting the value of $\frac{V^2}{R}$,we get $P_p = 2 	imes 120 = 240 \, W$.

Two equal resistances when connected in series to a battery,consume electric power of $60 \, W$. If these resistances are now connected in parallel combination to the same battery,the electric power consumed will be .............. $W$.

Similar Questions

In the circuit shown,the thermal power dissipated in $R_1$ is $P$. The thermal power dissipated in $R_2$ is

In the circuit diagram shown below,the magnitude and direction of the flow of current respectively would be

In the given circuit,the value of $\left|\frac{I_1+I_3}{I_2}\right|$ is

If three bulbs $60\,W$,$100\,W$ and $200\,W$ are connected in parallel,then

An electric current is passed through a circuit containing two wires of the same material,connected in parallel. If the lengths and radii of the wires are in the ratio of $4/3$ and $2/3$ respectively,then the ratio of the currents passing through the wires will be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module