Two full turns of the circular scale of a scr | vedclass

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(A) The pitch of the screw gauge is the distance moved in one full rotation. Since $2$ full turns cover $1 \ mm$,the pitch $= \frac{1 \ mm}{2} = 0.5 \

Vedclass · Accepted Answer

$3.38$

Vedclass · Answer

(A) The pitch of the screw gauge is the distance moved in one full rotation. Since $2$ full turns cover $1 \ mm$,the pitch $= \frac{1 \ mm}{2} = 0.5 \ mm$.The least count $(LC)$ is given by $\frac{	ext{pitch}}{	ext{total number of divisions}} = \frac{0.5 \ mm}{50} = 0.01 \ mm$.The observed reading is calculated as: $	ext{Main Scale Reading} + (	ext{Circular Scale Division} 	imes LC) = 3 \ mm + (35 	imes 0.01 \ mm) = 3.35 \ mm$.The actual diameter is calculated by subtracting the zero error from the observed reading: $	ext{Diameter} = 	ext{Observed Reading} - (	ext{Zero Error}) = 3.35 \ mm - (-0.03 \ mm) = 3.35 \ mm + 0.03 \ mm = 3.38 \ mm$.

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