Two isomers A and B with molecular formula C_ | vedclass

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(D) The molecular formula $C_4H_8$ corresponds to alkenes. Oxidation of alkenes with acidic $KMnO_4$ leads to cleavage of the double bond. $2-$methylp

Vedclass · Accepted Answer

$2-$methylpropene

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(D) The molecular formula $C_4H_8$ corresponds to alkenes. Oxidation of alkenes with acidic $KMnO_4$ leads to cleavage of the double bond. $2-$methylpropene $(CH_3)_2C=CH_2$ on oxidation with acidic $KMnO_4$ gives acetone $(CH_3)_2C=O$ and $CO_2$ gas,which causes effervescence. The reaction is: $(CH_3)_2C=CH_2 + [O] \xrightarrow{KMnO_4/H^+} (CH_3)_2C=O + CO_2 + H_2O$. Thus,compound $A$ is $2-$methylpropene.

Two isomers $A$ and $B$ with molecular formula $C_4H_8$ give different products on oxidation with $KMnO_4$ in acidic medium. Isomer $A$ on reaction with $KMnO_4 / H^{+}$ results in effervescence of a gas and gives a ketone. The compound $A$ is ...... .

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