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(A) The reaction of an alkene with $Br_2$ proceeds via the formation of a cyclic bromonium ion intermediate. The $Br^-$ ion then attacks the bromonium

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(A) The reaction of an alkene with $Br_2$ proceeds via the formation of a cyclic bromonium ion intermediate. The $Br^-$ ion then attacks the bromonium ion from the side opposite to the bridged bromine atom, resulting in anti-addition. For the given alkene, $CH_3-CH=CH-C_2H_5$ (pent$-2-$ene), the anti-addition of $Br_2$ leads to the formation of a pair of enantiomers as the major products. These are represented by the structures in options $A$ and $D$ (or equivalent representations of the enantiomeric pair).

The major products obtained in the following reaction is/are:
$CH_3-CH=CH-C_2H_5 + Br_2 \rightarrow ?$

Similar Questions

$CH_3-CH(CH_3)-CH=CH_2 + HBr \to X$ (product)
What is the major product $X$ in the reaction?

Write the main product of the given reactions:
$(1)$ $CH_3CH = CHCH_3 + HBr \to$
$(2)$ $CH_3-C(CH_3)=CH_2 + HBr \to$

The product $(P)$ is:

$Ph-CH=C(CH_3)_2 \xleftarrow{HBr} A$ and $Ph-CH=C(CH_3)_2 \xrightarrow[\text{Peroxide}]{HBr} B$. Identify $A$ and $B$.

The number of acyclic structural isomers (including geometrical isomers) for pentene $(C_5H_{10})$ are $......$

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The major products obtained in the following reaction is/are: $CH_3-CH=CH-C_2H_5 + Br_2 \rightarrow ?$