Two long conductors separated by a distance $d$ carry currents $I_1$ and $I_2$ in the same direction. They exert a force $F$ on each other. Now,the current in one of them is increased to $2$ times and its direction is reversed. The distance between them is also increased to $3d$. The new value of force between them is:
- A$-2F$
- B$\frac{F}{3}$
- C$\frac{-2F}{3}$
- D$\frac{-F}{3}$
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