Two long parallel wires are at a distance 2d | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let the two wires be located at $x = -d$ and $x = +d$. Both carry current $I$ in the outward direction (positive $z$-axis). The magnetic field due

Vedclass · Accepted Answer

Vedclass · Answer

(A) Let the two wires be located at $x = -d$ and $x = +d$. Both carry current $I$ in the outward direction (positive $z$-axis). The magnetic field due to a wire at distance $r$ is $B = \frac{\mu_0 I}{2\pi r}$.Using the right-hand rule, the magnetic field due to the left wire at a point $x$ is $B_1 = \frac{\mu_0 I}{2\pi (x + d)}$ (directed upwards for $x > -d$).The magnetic field due to the right wire at a point $x$ is $B_2 = -\frac{\mu_0 I}{2\pi (d - x)}$ (directed downwards for $x The net magnetic field is $B_{net} = B_1 + B_2 = \frac{\mu_0 I}{2\pi} \left( \frac{1}{x+d} - \frac{1}{d-x} \right)$.At the midpoint $x = 0$, $B_{net} = \frac{\mu_0 I}{2\pi} (\frac{1}{d} - \frac{1}{d}) = 0$.For $x For $x > d$, both fields are directed upwards, so $B_{net}$ is positive.Between the wires $(-d < x < d)$, the field changes from negative to positive, passing through zero at $x = 0$. This corresponds to the graph shown in the solution image.

Two long parallel wires are at a distance $2d$ apart. They carry steady equal currents flowing out of the plane of the paper as shown. The variation of magnetic field $B$ along the line $XX'$ is given by

Similar Questions

The magnitude of the magnetic field at $O$ due to a current-carrying loop as shown in the figure is, where $O$ is the center of two circular portions with radii $1 \, cm$ and $2 \, cm$ respectively. (Take the value of current $I = \frac{1.2}{\pi} \, A$)

The ratio of the magnetic field at the centre of a current-carrying circular wire and the magnetic field at the centre of a square coil made from the same length of wire will be

$A$ current of $10\,A$ is passing through a long wire which has a semicircular loop of radius $20\,cm$ as shown in the figure. The magnetic field produced at the centre $P$ of the loop is:

Two concentric and coplanar rings of radius $r$ and $R$ are shown in the figure. Find the magnetic flux linked through the smaller coil when the same current $I$ flows through each in opposite directions $(r << R)$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module