Two masses $M_1$ and $M_2$ are accelerated uniformly on a frictionless surface as shown in the figure. The ratio of the tensions $T_1/T_2$ is:

$A$ light string passing over a smooth light pulley connects two blocks of masses $m_1$ and $m_2$ (where $m_2 > m_1$). If the acceleration of the system is $\frac{g}{\sqrt{2}}$,then the ratio of the masses $\frac{m_1}{m_2}$ is:

$A$ particle of small mass $m$ is joined to a very heavy body of mass $M$ by a light string passing over a light pulley. Both bodies are free to move. The total downward force on the pulley is

$A$ block of mass $1\,kg$ is suspended by a string of mass $1\,kg$ and length $1\,m$ as shown in the figure. $(g = 10\,m/s^2)$. Calculate the tension (in $N$) in the string at its lowest point.

$A$ hanging mass $M$ is connected to a four times larger mass $(4M)$ by using a string-pulley arrangement as shown in the figure. The larger mass is placed on a horizontal ice slab and is being pulled by a $2Mg$ force. In this situation,the tension in the string is $\frac{x}{5}Mg$. Find the value of $x$. Neglect the mass of the string and the friction between the block (larger mass) and the ice slab. (Given $g$ = acceleration due to gravity)

In the given figure,two masses $m_1$ and $m_2$ $(m_2 > m_1)$ are at rest in an equilibrium position. Find the tension in string $AB$.