Two non-reactive monoatomic ideal gases have | vedclass

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(D) The ideal gas equation is given by $PV = nRT$,where $n = \frac{m}{M}$.Since $n = \frac{m}{M}$,we can write $P = \frac{m}{V} \frac{RT}{M} = \frac{\

Vedclass · Accepted Answer

$8 : 9$

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(D) The ideal gas equation is given by $PV = nRT$,where $n = \frac{m}{M}$.Since $n = \frac{m}{M}$,we can write $P = \frac{m}{V} \frac{RT}{M} = \frac{ho RT}{M}$,where $ho$ is the density.Thus,the ratio of partial pressures is given by $\frac{P_1}{P_2} = \frac{ho_1 M_2}{ho_2 M_1}$.Given $\frac{M_1}{M_2} = \frac{2}{3}$ and $\frac{P_1}{P_2} = \frac{4}{3}$.Substituting these values: $\frac{4}{3} = \frac{ho_1}{ho_2} 	imes \frac{3}{2}$.Therefore,$\frac{ho_1}{ho_2} = \frac{4}{3} 	imes \frac{2}{3} = \frac{8}{9}$.

Two non-reactive monoatomic ideal gases have their atomic masses in the ratio $2 : 3$. The ratio of their partial pressures,when enclosed in a vessel kept at a constant temperature,is $4 : 3$. The ratio of their densities is :-

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