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(C) Given that the two parallel plate capacitors have the same charge $q$ and the same potential $V$, their capacitances must be equal because $C = q/

Vedclass · Accepted Answer

$0.25$

Vedclass · Answer

(C) Given that the two parallel plate capacitors have the same charge $q$ and the same potential $V$, their capacitances must be equal because $C = q/V$.Therefore, $C_1 = C_2$.The formula for the capacitance of a parallel plate capacitor is $C = \frac{\varepsilon_0 A}{d}$.Equating the two capacitances: $\frac{\varepsilon_0 A_1}{d_1} = \frac{\varepsilon_0 A_2}{d_2}$.This simplifies to $d_2 = \frac{A_2}{A_1} d_1$.Given $A_1 = 100 \,cm^2$, $A_2 = 500 \,cm^2$, and $d_1 = 0.5 \,mm = 0.05 \,cm$.Substituting these values: $d_2 = \frac{500}{100} 	imes 0.05 \,cm = 5 	imes 0.05 \,cm = 0.25 \,cm$.

Two parallel air capacitors have their plate areas $100 \,cm^2$ and $500 \,cm^2$, respectively. They have the same charge and potential. If the distance between the plates of the first capacitor is $0.5 \,mm$, the distance between the plates of the second capacitor is (in $\,cm$)

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