Two places P and Q are 162 , km apart. A trai | vedclass

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(C) Let the speed of the train from $Q$ be $x \, km/h$.Since the train from $P$ is $8 \, km/h$ faster,its speed is $(x + 8) \, km/h$.When two objects

Vedclass · Accepted Answer

$9 \frac{1}{2}$

Vedclass · Answer

(C) Let the speed of the train from $Q$ be $x \, km/h$.Since the train from $P$ is $8 \, km/h$ faster,its speed is $(x + 8) \, km/h$.When two objects move towards each other,their relative speed is the sum of their individual speeds: $(x + x + 8) = (2x + 8) \, km/h$.Given that they meet after $6 \, hours$ and the total distance is $162 \, km$,we use the formula: $	ext{Distance} = 	ext{Relative Speed} 	imes 	ext{Time}$.$162 = (2x + 8) 	imes 6$.Divide both sides by $6$: $27 = 2x + 8$.Subtract $8$ from both sides: $2x = 19$.Divide by $2$: $x = 9.5 \, km/h$,which is $9 \frac{1}{2} \, km/h$.

Two places $P$ and $Q$ are $162 \, km$ apart. $A$ train leaves $P$ for $Q$ and simultaneously another train leaves $Q$ for $P$. They meet at the end of $6 \, hours$. If the former train travels $8 \, km/h$ faster than the other,then the speed of the train from $Q$ is (in $km/h$):

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