Two point charges +8q and -2q are located at | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The net electric field will be zero at a point outside the charges and closer to the charge which is smaller in magnitude.Let the point $P$ be at

Vedclass · Accepted Answer

$2\,L$

Vedclass · Answer

(C) The net electric field will be zero at a point outside the charges and closer to the charge which is smaller in magnitude.Let the point $P$ be at a distance $l$ from the charge $-2q$ at $x = L$. The distance of $P$ from the charge $+8q$ at $x = 0$ is $(L + l)$.At point $P$,the magnitude of the electric field due to $+8q$ must be equal to the magnitude of the electric field due to $-2q$:$\frac{k \cdot |8q|}{(L + l)^2} = \frac{k \cdot |2q|}{l^2}$Simplifying the equation:$\frac{8}{(L + l)^2} = \frac{2}{l^2}$$\frac{4}{(L + l)^2} = \frac{1}{l^2}$Taking the square root on both sides:$\frac{2}{L + l} = \frac{1}{l}$$2l = L + l$$l = L$The position of point $P$ on the $x$-axis is $x = L + l = L + L = 2L$.

Two point charges $+8q$ and $-2q$ are located at $x = 0$ and $x = L$ respectively. The location of a point on the $x$-axis at which the net electric field due to these two point charges is zero is

Similar Questions

Reduction of nitrobenzene with $Zn$ and alcoholic $KOH$ solution results in the formation of the following compound:

Which of the following is the simplest amino acid?

The maximum value of $\sin (\cos (\tan x))$ is

Phosgene is formed slowly from which one of the following on exposure to air and sunlight?

Which of the following is the simplest amino acid?

Vedclass Test Series

Exam Paper Generator

Online Exam Module