Two point unlike charges having magnitudes +1 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given: $q_1 = +16 \mu C$,$q_2 = -9 \mu C$,distance $d = 10 \ cm$.Let the point where the resultant electric field is zero be at a distance $x$ fro

Vedclass · Accepted Answer

$30$

Vedclass · Answer

(D) Given: $q_1 = +16 \mu C$,$q_2 = -9 \mu C$,distance $d = 10 \ cm$.Let the point where the resultant electric field is zero be at a distance $x$ from the $-9 \mu C$ charge. Since the charges are unlike,the null point lies outside the region between the charges,closer to the charge with the smaller magnitude.At the null point,the magnitude of the electric field due to $q_1$ must equal the magnitude of the electric field due to $q_2$.$E_1 = E_2$$\frac{k |q_1|}{(d + x)^2} = \frac{k |q_2|}{x^2}$$\frac{16}{(10 + x)^2} = \frac{9}{x^2}$Taking the square root on both sides:$\frac{4}{10 + x} = \frac{3}{x}$$4x = 3(10 + x)$$4x = 30 + 3x$$x = 30 \ cm$Thus,the resultant electric field is zero at a distance of $30 \ cm$ from the $-9 \mu C$ charge.

Two point unlike charges having magnitudes $+16 \mu C$ and $-9 \mu C$ are separated by a distance of $10 \ cm$ in air. The resultant electric field will be zero at a distance of . . . . . . from the $-9 \mu C$ charge. (in $cm$)

Similar Questions

The electric field lines on the left have twice the separation of those on the right as shown in the figure. If the magnitude of the electric field at $A$ is $40 \ Vm^{-1}$,what is the force on a $20 \ \mu C$ charge kept at $B$?

Two point charges of $20\,\mu C$ and $80\,\mu C$ are $10\,cm$ apart. Where will the electric field strength be zero on the line joining the charges from the $20\,\mu C$ charge? (in meters)

At a certain distance from a point charge,the electric field is $500\,V/m$ and the potential is $3000\,V$. What is this distance in meters?

What is the electric field at the center of a semi-circular ring of radius $R$ having a linear charge density $\lambda$? $\left( k = \frac{1}{4\pi \varepsilon_0} \right)$

Four equal charges of value $+Q$ are placed at four vertices of a regular hexagon of side $a$. By suitably choosing the vertices, what can be the maximum possible magnitude of the electric field at the centre of the hexagon?

Vedclass Test Series

Exam Paper Generator

Online Exam Module