Two thin lenses having R_1 and R_2 as the rad | vedclass

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(D) According to the Lens Maker's Formula,the power $P$ of a thin lens is given by $P = \frac{1}{f} = (\mu - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \

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$\frac{R_1+R_2}{R_1 R_2}$

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(D) According to the Lens Maker's Formula,the power $P$ of a thin lens is given by $P = \frac{1}{f} = (\mu - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)$.For a combination of two thin lenses kept coaxially in contact,the equivalent power $P_{eq}$ is the sum of the individual powers: $P_{eq} = P_1 + P_2$.Each power $P_i$ is proportional to the term $\left( \frac{1}{R_{i,1}} - \frac{1}{R_{i,2}} \right)$.Considering the general form of the lens power,it is proportional to the sum of the reciprocals of the radii of curvature,which simplifies to the form $\frac{R_1+R_2}{R_1 R_2}$ when considering the additive nature of the curvatures.Therefore,the power is proportional to $\frac{R_1+R_2}{R_1 R_2}$.

Two thin lenses having $R_1$ and $R_2$ as the radii of curvature of their surfaces are kept coaxially together. Their power is proportional to

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